Tricky Puzzles - Topic 3

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Jutomi
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Post by Jutomi » Mon Mar 31, 2014 4:16 pm

Important news says that there are more secret rooms, but they're rather buried, and I am sure this excavation has gone on long enough.

Research tells that these symbols are actually made at approximately Dr. Chip Snack Neaf's level.

Or, ratherly, his levels...

My final answer, which I will now share to the public, will be in a quote box.

Please do let me know if any of you have come close to what is yet to come. :mrgreen:
The Doctor wrote:Fascinating! These happen to be somewhat poorly-drawn maps of the layout of the rooms that the Knights of the Folding Table have encountered!
I wonder who drew them...
and why they were there to begin with.
I think I have the answer to that, too; and, I am sure you guys can guess that easier than this. :D
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Post by Jutomi » Sun Apr 13, 2014 9:37 pm

Sorry for bumping this up, but...

after replying to Epicdude, I realized that I never gave the answer of my last chess puzzle. :|

Here it lies! :D

Note: Black side = the side black starts on; black pawns move to white side, white pawns move to black side.
An other note: There may be more than one answer to this.
Attachments
Chesspuzzleanswer_Mo.png
This personality made me search for this for ages.
Chesspuzzleanswer_Mo.png (10.89 KiB) Viewed 5189 times
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Post by LittleZbot » Mon Apr 14, 2014 5:05 am

I'm surprised no-one has put this on yet. It's the famous "Einstein's Riddle," the logic test that only 2% of the world can solve. I solved it in a little over ten minutes. So go ahead, try your best.


There are 5 houses in 5 different colors. In each house lives a person with a different nationality. The 5 owners drink a certain type of beverage, smoke a certain brand of cigar, and keep a certain pet. No owners have the same pet, smoke the same brand of cigar, or drink the same beverage.

The question is: Who owns the fish?

Hints:

The Brit lives in the red house.
The Swede keeps dogs as pets.
The Dane drinks tea.
The green house is on the left of the white house.
The green homeowner drinks coffee.
The person who smokes Pall Mall rears birds.
The owner of the yellow house smokes Dunhill.
The man living in the center house drinks milk.
The Norwegian lives in the first house.
The man who smokes Blend lives next to the one who keeps cats.
The man who keeps the horse lives next to the man who smokes Dunhill.
The owner who smokes Bluemaster drinks beer.
The German smokes prince.
The Norwegian lives next to the blue house.
The man who smokes Blend has a neighbor who drinks water.
To Shorty, who was immortalized in an adventure.
To Marinus, who was my community older brother.
To Janet, who I will remember every time I wear a toque.

May these lost Wonderlanders find true adventure beyond us.
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Post by Muzozavr » Mon Apr 14, 2014 8:17 am

Jutomi wrote:Sorry for bumping this up, but...

after replying to Epicdude, I realized that I never gave the answer of my last chess puzzle. :|

Here it lies! :D

Note: Black side = the side black starts on; black pawns move to white side, white pawns move to black side.
An other note: There may be more than one answer to this.
I'm sorry, but that was flawed as all hell. It does have the potential to be a great little puzzle, but right now the rules are in desperate need of fixing.

First of all, one "move" in chess means one move for white AND one move for black. Move/reply, move/reply. So if you meant "white moves, black moves, white moves" you should've phrased things differently or specified this in the rules.

Second,
four chess pieces
ASIDE from the queens, right? But your diagram has three. Rook, bishop, pawn.

The version in your diagram is flawed because white can just go Qf3, then black can move the bishop away and white can take the queen. Since you said "four chess pieces" you can add another piece (a pawn, for example) on c6 to prevent that from happening.

You also need to change "attack" into "take" in the rules because even after THAT you can go 1. Qf3 c5 2. Q:b7 (taking the bishop) and the queens are attacking each other, even though they are both "alive" at this point.

Finally, the last problem is this part:
The rules of chess all apply here
First of all, that renders the entire puzzle useless, because a queen can be taken by a different piece and not the other queen. That makes the puzzle impossible. Even if you specify that in the rules, though (that only a queen can take the other queen) the last problem remains: according to chess rules, you can never have a black pawn at the 8th rank. It just doesn't happen in-game and is a violation of the rules in and of itself. Replacing that pawn with a second rook (and adding a pawan on c6, as I described) makes for a more "proper" solution and fixes the puzzle.

There's no anger in my words and I'm not trying to offend you personally, the puzzle is just flawed. Fixing it, however, could make it into an insteresting little challenge, so... yeah, thank you, anyway. 8)
Rest in peace, Kym. I hardly knew ya.
Rest in peace, Marinus. A bright star, you were ahead of me on my own tracks of thought. I miss you.
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Post by Qloof234 » Mon Apr 14, 2014 9:09 am

LittleZbot wrote:I'm surprised no-one has put this on yet. It's the famous "Einstein's Riddle," the logic test that only 2% of the world can solve. I solved it in a little over ten minutes. So go ahead, try your best.


There are 5 houses in 5 different colors. In each house lives a person with a different nationality. The 5 owners drink a certain type of beverage, smoke a certain brand of cigar, and keep a certain pet. No owners have the same pet, smoke the same brand of cigar, or drink the same beverage.

The question is: Who owns the fish?

Hints:

The Brit lives in the red house.
The Swede keeps dogs as pets.
The Dane drinks tea.
The green house is on the left of the white house.
The green homeowner drinks coffee.
The person who smokes Pall Mall rears birds.
The owner of the yellow house smokes Dunhill.
The man living in the center house drinks milk.
The Norwegian lives in the first house.
The man who smokes Blend lives next to the one who keeps cats.
The man who keeps the horse lives next to the man who smokes Dunhill.
The owner who smokes Bluemaster drinks beer.
The German smokes prince.
The Norwegian lives next to the blue house.
The man who smokes Blend has a neighbor who drinks water.
Oohoooh, man, I'm not sure whether I solved this through careful reasoning or through just being stubborn, but... Yeah. Took me about 20 minutes, but that was satisfying. 8)
Image
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Jutomi
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Post by Jutomi » Mon Apr 14, 2014 3:46 pm

Oh!

Yes, thanks for the moves and the bishop thing...

It's been so long, I forgot the answer to my own puzzle. :lol:

Yes, I thought I put a king in front of the bishop.

I forget why, and am just waking up, so... :?

Though, about the "All chess rules apply here"...

I meant things like "Pawns become any thing - even queens" thing applied.
But do all so note that all queens will do whatever it takes to take each other off of the board - and the other pieces will gladly help with that.
I suppose that's not very specific, as what I meant was that they'd help either one of the queens get rid of the other; they'd never take them off, themselves.
Sorry about that. :mrgreen:
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Post by Jutomi » Tue Apr 15, 2014 4:39 am

Well, here I am with a hopefully more fair puzzle. :mrgreen:

It was actually inspired by Edison's puzzle, but I decided to make something flabbergastingly different from the original concept.

This should all so be somewhat easier. :mrgreen:

So, what are the symbols from this code?
I.E. T2XS9V8B1FF5E3C or something like that.
Attachments
Encryption.png
I can even find it in this mode, yay!
Encryption.png (5.11 KiB) Viewed 5141 times
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Post by Jutomi » Wed Apr 16, 2014 1:20 am

Note: I think I misspelled "Seek"... oops ,_,
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Post by yot yot5 » Thu Apr 17, 2014 10:15 am

LittleZbot wrote:I'm surprised no-one has put this on yet. It's the famous "Einstein's Riddle," the logic test that only 2% of the world can solve. I solved it in a little over ten minutes. So go ahead, try your best.


There are 5 houses in 5 different colors. In each house lives a person with a different nationality. The 5 owners drink a certain type of beverage, smoke a certain brand of cigar, and keep a certain pet. No owners have the same pet, smoke the same brand of cigar, or drink the same beverage.

The question is: Who owns the fish?

Hints:

The Brit lives in the red house.
The Swede keeps dogs as pets.
The Dane drinks tea.
The green house is on the left of the white house.
The green homeowner drinks coffee.
The person who smokes Pall Mall rears birds.
The owner of the yellow house smokes Dunhill.
The man living in the center house drinks milk.
The Norwegian lives in the first house.
The man who smokes Blend lives next to the one who keeps cats.
The man who keeps the horse lives next to the man who smokes Dunhill.
The owner who smokes Bluemaster drinks beer.
The German smokes prince.
The Norwegian lives next to the blue house.
The man who smokes Blend has a neighbor who drinks water.
Yeah, I've solved this one before. I can't remember the answer, but it took me about 30 minutes.
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Sum-Free Partitions Puzzle

Post by VirtLands » Wed Apr 23, 2014 11:07 pm


Just for fun.
Here's a new puzzle, ( this one is apparently extremely difficult. :shock: )


PUZZLE A:
It is called the Sum-Free partitions puzzle. { Schur's Problem }

-- A stream of counting numbers (1,2,3,4,....) flows downward
and each number must in turn be placed in 1 of 3 hats
in such a way that no 2 previous numbers sum up to the new number.

Your obvious goal is to place as many numbers there as possible, individual results shall vary.

[ This screenshot shows a failed state, -- the number 10 is not welcome in any hat. ]

Image
-----
It has apparently been proven that there is no infinite solution, only various finite sequences, which fail.

Your new goal, should you wish to accept it, is to change the
rules of this puzzle in some imaginative way, such that an infinite
(or nearly infinite) solution may exist.


for reference:
http://mathworld.wolfram.com/SchursProblem.html
http://www.emis.de/journals/INTEGERS/papers/g7/g7.pdf
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Puzzle B

Post by VirtLands » Wed Apr 23, 2014 11:45 pm

..
PUZZLE B:
Here is yet another very diabolically hard puzzle. :wink:

You have 57 points (also known as NODES).

You may arrange these 57 nodes in any convenient pattern you wish;
but usually it's best to place them in a circular pattern (on paper).

Here is your goal :::
Every single node in that set must mutually connect to exactly 6 other nodes, ( not more, and not less! )

This can be demonstrated by drawing lines from node to node.

It can also be done through a computer program, [in C, or BASIC]

Demonstrate that each node (out of 57) can be connected to exactly 6 others.

Good Luck.
---------------------------------------
If anyone tries to accomplish PUZZLE A or PUZZLE B then I'll come back with even harder puzzles....
Last edited by VirtLands on Thu Apr 24, 2014 7:31 pm, edited 1 time in total.
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Re: Sum-Free Partitions Puzzle

Post by LittleZbot » Thu Apr 24, 2014 3:47 am

VirtLands wrote: Your new goal, should you wish to accept it, is to change the
rules of this puzzle in some imaginative way, such that an infinite
(or nearly infinite) solution may exist.
Adding negative numbers to the mix could do the trick.

Maybe.
To Shorty, who was immortalized in an adventure.
To Marinus, who was my community older brother.
To Janet, who I will remember every time I wear a toque.

May these lost Wonderlanders find true adventure beyond us.
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Re: Puzzle B

Post by yot yot5 » Thu Apr 24, 2014 8:49 am

VirtLands wrote:..
PUZZLE B:
Here is yet another very diabolically hard puzzle. :wink:

You have 57 points (also known as NODES).

You may arrange these 57 nodes in any convenient pattern you wish;
but usually it's best to place them in a circular pattern (on paper).

Here is your goal :::
Every single node in that set must mutually connect to exactly 6 other nodes, ( not more, and not less! )

This can be demonstrated by drawing lines from node to node.

It can also be done through a computer program, [in C, or BASIC]

Demonstrate that each node (out of 57) can be connected to exactly 6 others.

Good Luck.
---------------------------------------
If anyone accomplishes PUZZLE A or PUZZLE B then I'll come back with even harder puzzles (as your reward).
Ooh, I haven't done this one, but I've heard a lot about puzzles like this.
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57-cell puzzle clues

Post by VirtLands » Thu Apr 24, 2014 11:25 pm

Concerning PUZZLE A:
LittleZbot wrote:Adding negative numbers to the mix could do the trick.
Maybe.
I shall try that sometime, that's an interesting variation.
I don't know if it shall work.

Some option 1: The numbers may be forced to become negative if and only if all 3 hats are forbidden...
allowing for the possibility of an infinite solution.

-----------------------------------------------------------------------------------------------------------

Concerning PUZZLE B: [ 57-cell, perkel graph, & pentacontaheptachoron ]

Here is a clue ,
57 points (vertices) are arranged in a circular fashion, each point connects to exactly 6 other points ::::

There are apparently 9 regular ways to do this.
My belief is that all 9 graphs are identical and topologically equivalent, but I'm not sure. Click to see the variations ::

http://tinyurl.com/k3nvkyx
http://tinyurl.com/o5oypb8

Image

It would be interesting to see those connected (57) vertices in some kind of set notation,

such as {A,B,C,D} U {C,D,E,F} U {E,G,H,I} U ....
or such as {A,B,C,D,E,F} U {E,F,G,H,I,J} U {H,I,J,K,L,M} U ...

Vertices shall be identified by letters, A,B,C,D,...
U = the union symbol

Creating an accurate representation of the 57-cell
in set notation would be kind of complex, probably. ;)
I haven't tried that yet; I guess it's a project for another time.


{ A,B,C,D } can be read as
-- A is connected to B,
-- B is connected to C,
-- C is connected to D


references ::
Venn Diagrams and Set Notation --> http://www.purplemath.com/modules/venndiag2.htm
https://en.wikipedia.org/wiki/File:Perk ... ddings.svg
http://mathworld.wolfram.com/57-Cell.html
http://archive.today/dbE6n
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Post by Jutomi » Fri Apr 25, 2014 3:41 am

Virt...

You really should make wonderland levels. :lol:

You might make the toughest ones this forum has ever seen. :lol:

Here's a hint to my previous puzzle:
Jutomi wrote:C0d3 1z af10 xs a tr1ke th1ng.
0th3r tims, its n0t 2o d1fika1t. :mrgreen:
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Post by Jutomi » Fri May 23, 2014 5:04 pm

Well, here's the answer - finally - to my puzzle. :P

I do must have to admit, though, that my explanation to the thing was somewhat vague, the answer to what you're looking for is to
Jutomi wrote:Every word like "Cat" or "Bone" is hidden within the text - in a different form, though. Like, "sixes" would be "6S", and then saying "Nine sixes" = 9 6S, or, in this case, 96S.
The answer to the puzzle of mine is listed below. :mrgreen:
Jutomi wrote:(5E3/C)1F1(4T/8)4224T4C4T5E3C44C4TB1
Translated:
5E3/C, 1F 1 4T/8 4 22 4T 4 C4T, 5E3C 4 4 C4T B1.
Translated:
See(cee), <i>f 1(one) ate(8 or long a, t) a too-too at a seat(aka (cee)(a<silent like in the word itself>)(t sound)), seek <for> <a> c<4>t b(one).
Cleaned up:
See, if one ate a too-too at a seat, seek for a cat bone.
That's that!
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Jutomi's puzzles

Post by VirtLands » Sat May 24, 2014 9:04 pm

Jutomi wrote:Every word like "Cat" or "Bone" is hidden within the text - in a different form, though. Like, "sixes" would be "6S", and then saying "Nine sixes" = 9 6S, or, in this case, 96S.
Well, that was a difficult puzzlement.

Nine sixes = 9 6S, or = 96S.


The potential confusion there is that it can also be read 96 S.

..
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Post by Jutomi » Sat May 24, 2014 10:26 pm

Ah, yes...

but remember, we're trying to give a code to the sentence, not the vice versa. :mrgreen:

Otherwise, I probably would have kept the spaces. :lol:

Also, just out of curiosity...

Any body else open for puzzles? :P

If not, here's one any ways. :D

Now, I've been fascinated in the patterns of dimensional cubes and their angles / edges.

I've noticed that there does seem to be a pattern, but by the time it gets to the -dimensions, they seem to give some...
unusual numbers. :P

Well, I've put together a simple thing based off of this idea.

Say you take figure 1 as the first dimension.
You notice 3 circles....
and, you notice that there are three sets of lines.
The first set of potential lines is the physical lines, to which can't pass through other lines or other circles.
The second set of potential lines is the cross lines, to which can't intercept any other circles, but crossing lines is fine.
The third set of potential lines is the passive lines, to which can pass through any circle and any line.
If you want to talk about lines that can pass through other lines, but not circles, that's up to you. :P

Now, due to the confusion that the first set might have with cancellation and domination ideas, lets just stick with the cross and passive lines.

You see how in the first figure, there are two cross lines that can be created - one between left and middle, one between middle and right.
There are all so three passive lines, which connect between left and middle, middle and right, and left and right.

Therefor, the solution for figure 1, or "1D", is 3C(circles), 2cl(cross lines), 3pl(passive lines)
1D=3C2cl3pl. :mrgreen:

Now, in the second figure, you see there are five circles

If you know any thing about squares and lines, and their points and angles and stuff, than this should be fairly easy for you to conceptualize.
Or.. at least, if there are 2, 4 circles.
But 3, 5, might make this a bit more confusing. :mrgreen:

The solution to this figure is, if you want a spoiler,
Jutomi, the mad z... I mean, stinker, wrote:2D=5C8cl10pl
Now, feel free to tell me if you disagree with any of these terms. :lol:

My question is...

What would be the solution for the third dimension?

And, if you want to imagine it, what would the solutions be for the -1st, 0th, 4th, and 7th dimensions?

Realize that since there's no way to prove that stuff, that's just if you want to show me your concepts. :lol:

I hope you enjoy! :D
Attachments
5 of the 2nd.png
Figure 2.
5 of the 2nd.png (5.37 KiB) Viewed 4994 times
3 of the 1st.png
Figure 1!
3 of the 1st.png (2.45 KiB) Viewed 4994 times
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Post by Jutomi » Sun May 25, 2014 8:39 pm

Time to give a hint!
Ah, yes, a very subtle hint. :lol:
Jutomi wrote:You may notice a pattern with the _ and X.
You may also notice another pattern!
You might even notice...(this is getting ridiculous, I know) the way they're aligned.
Jutomi also wrote:The thing is...
if this is a thing about squares, then why is there an x, and not a square..?
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Post by Jutomi » Sat May 31, 2014 5:53 pm

Here's another picture to perhaps help you along. :mrgreen:
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2 of the 0th.png
Hmm...
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Post by Jutomi » Sat Jun 07, 2014 11:47 pm

I have a feeling this thread's either falling out of favor, or I'm making puzzles that are too tricky... :?

I don't want to start off by making a quintople post within half a year, so, here's my last post until something happens with it. :P

Here's a more powerful hint for the previous question:
[color=yellow]Jutomi[/color], the unfortunate whimsy of the tricky puzzles 3 topic, wrote:Each dimentional square seems to follow a pattern of multiplication and addition / devision and subtraction.
Now, the number of circles appears to be some kind of vertex of any square + a centralized circle.
In other words, the first dimension has three circles because of its two ends and 1 centre(2+1=3), and the second dimension has five circles because its square has four corners and 1 centre(4+1=5)
Here's another part to the long text above. :mrgreen:
[color=yellow]Jutomi[/color], who's fitting as much as he can into one post, wrote:The lines connect either from every dot to every other dot(passive lines), or do the same, but can't pass through another dot(crosslines).
There's a set, and incredibly basic, pattern to the amount of crosslines per dimension.
From that, there's another pattern that determines the difference from the amount of crosslines to passivelines per dimension.
And here is one last thing that could really help significantly, if you find the huge text above difficult to understand. :)
[color=yellow]Jutomi[/color] continuously wrote:The answer for each circle, crossline, and passive line is a matter of being able to add and multiply - that's all.
~~~~~~~~~~~~~~~~~~~~~~~
I do have another question that you could answer for me. :mrgreen:

I've been somewhat fascinated in these things called "decoders", which involve trying to figure out numbers from number sequences.
I have made something similar to that extent via this text:

A+B=C
C-(AxB)=D
AxA=B-D
|D+D|=C+A
B+(AxC)=DxD
|(DxA)+C|=B+B
(BxB)+(AxA)=DxD
(Ax(C-D))-(BxB)-D=|((D^A)-D)/(AxB)+(DxA)|
(AxBxA)+(BxD)=(B^A)-(CxB)+(DxA)
|(CxDxC)+(C^A)-(A^B)|+(CxB)=(?x?)-?


The question is...
What letters are ?, ?, and ?
They MUST be either A, B, C, or D.

You may all so try guessing what numbers A, B, C, and D represent. :mrgreen:

I hope you fine this baffling, but not too baffling. :D

If you figure out the first few parts, chances are you'll figure out the later, as well.
All so, the numbers aren't "huge" like &#8805;20 or something.
And, finally, no number is repeated(In other words, A does not equal B, etc.)

Have fun. :mrgreen:
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Post by SearchForReality » Tue Jun 10, 2014 2:55 am

Whoa, this is a BIG collection of puzzles! I have got to get my hands on some of these. Virtual hands, anyways.
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Post by StinkerSquad01 » Tue Jun 10, 2014 5:44 am

Well, virtual hands are the best hands. You can reach more with them than you can with your actual hands. Or can you?
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Jutomi
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Post by Jutomi » Tue Jun 10, 2014 4:09 pm

Thanks for replying so I can post on here again. :lol:

Here's the answer to a question I made a fair while ago - one which was never answered.
Jutomi, the who seems to forget certain things, wrote:Here's an other one for you - and it's not calculus. :mrgreen:

76=3171, 587=8102, and 1462=115.

What would 5000 be?
Mind you that I believe the correct answer for 587 was 882... :?

Oh well, at least the other two were correct.

So, from what I have calculated(Really, I had to use a calender, a system clock, and a calculator), the answer to 5000 is...(I'm pretty sure...)
Jutomi wrote:9913
The reasoning behind this is ratherly a quite peculiar one...

and, it shall be shown in this text box below this message.
Jutomi wrote:The first number is the amount of days counted up after the day of 1/0/1(which doesn't exist, of course, but you know.) That means 1 = 1/1/1.
The second number is the m/d/y date - but without the slashes.

To confirm the concept, 2=1/2/1, 3=1/3/1, 4=1/4/1, 31=1/31/1 32=2/1/1

And, because of this, the answer looks like 32=211.
I have to admit, that one was really quite extraordinarily mean...
I believe that these other two puzzles aren't nearly as cryptic. :lol:

P.S. If I'm so bad at calender stuff, why did I decide to not only make a question out of it? :|
Your only little stinker that's absolutely NOT a z-bot by this name,
Jutomi~ :mrgreen:

Also, if you want to see my level list, here it is! :D
(Also: List of Hubs, WA Manual)
Oh, and my YT wonderland channel. Forgot about that.
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yot yot5
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Post by yot yot5 » Tue Jun 10, 2014 6:27 pm

Jutomi wrote:A+B=C
C-(AxB)=D
AxA=B-D
|D+D|=C+A
B+(AxC)=DxD
|(DxA)+C|=B+B
(BxB)+(AxA)=DxD
(Ax(C-D))-(BxB)-D=|((D^A)-D)/(AxB)+(DxA)|
(AxBxA)+(BxD)=(B^A)-(CxB)+(DxA)
|(CxDxC)+(C^A)-(A^B)|+(CxB)=(?x?)-?


The question is...
What letters are ?, ?, and ?
They MUST be either A, B, C, or D.

You may all so try guessing what numbers A, B, C, and D represent. :mrgreen:
What does the ^ stand for?
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Wonderland King
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Post by Wonderland King » Tue Jun 10, 2014 6:47 pm

yot yot5 wrote:
Jutomi wrote:A+B=C
C-(AxB)=D
AxA=B-D
|D+D|=C+A
B+(AxC)=DxD
|(DxA)+C|=B+B
(BxB)+(AxA)=DxD
(Ax(C-D))-(BxB)-D=|((D^A)-D)/(AxB)+(DxA)|
(AxBxA)+(BxD)=(B^A)-(CxB)+(DxA)
|(CxDxC)+(C^A)-(A^B)|+(CxB)=(?x?)-?


The question is...
What letters are ?, ?, and ?
They MUST be either A, B, C, or D.

You may all so try guessing what numbers A, B, C, and D represent. :mrgreen:
What does the ^ stand for?
Exponents?
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SearchForReality
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Post by SearchForReality » Tue Jun 10, 2014 8:27 pm

I think that sign means multiplication.
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yot yot5
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Post by yot yot5 » Tue Jun 10, 2014 8:38 pm

SearchForReality wrote:I think that sign means multiplication.
Nah, the "x" stands for multiplication.
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Jutomi
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Post by Jutomi » Tue Jun 10, 2014 9:39 pm

+ = addition, - = subtraction, x = multiplication, / = division, ^ = to the power of, () = do that part before the part outside of them, (()) = do the central part before the outer part before every thing else, || = absolute value, = = is equal to. :mrgreen:
Your only little stinker that's absolutely NOT a z-bot by this name,
Jutomi~ :mrgreen:

Also, if you want to see my level list, here it is! :D
(Also: List of Hubs, WA Manual)
Oh, and my YT wonderland channel. Forgot about that.
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Jutomi
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Post by Jutomi » Thu Jun 26, 2014 9:05 pm

Well, I think it's about time I gave an explanation to the dimension and hint to the decoding puzzles. :mrgreen:

Lets start with the dimensional puzzle, shall I? Yes, of course I will.

Now, about the dimensional puzzle...

first, I shall explain about the circles.
Jutomi wrote:Each circle represents the very centre and the very edges of a square per dimension.
So, a cube has 8 ends, and the centre circle, thus giving it nine circles.
A square has 4 ends, and then the centre circle, giving it five circles.
A line has 2 ends, and a centre circle, giving it three circles total.
Next, about the lines...
Jutomi also wrote:Each line connects from one circle to another.
The passive lines link every one circle to every other circle.
The Cross lines link every one circle to every other circle in the first circle's line of sight; it can't pass through one circle to get to another.
So, because of this,
Jutomi wrote:The first dimension has 3 circles, 2 cross lines(the centre circle blocks the right from the left), and 3 passive lines(all circles are connected).
1D=3C2cl3pl
The second dimension has 5 circles(4 ends, 1 centre), 10 passive lines, and 8 cross lines.
2D=5C8cl10pl
The answer is:
Jutomi wrote:The third dimension has 9 circles, 32 cross lines, and 36 passive lines.
3D=9C32cl36pl.
Now, the pattern that I have noticed within these dimensional circles and lines is:
Jutomi the repetitive wrote:Every dimension, off of a base of 1-2, 2-3, and, presumably, 3-4, is based on multiplication.
Circles = x2 per dimension, + 1 to include the centre.
Crosslines = x4 per dimension, starting at 2 for the first dimension.
Passive lines = Crosslines per dimension + extra sum.
Extra Sum = x2 per every dimension, starting at 1 for 1st dimension.

1D=3(2+1),2,3(2+1). 2D=5(2x2+1),8(2x4),10(8+[1x2]). 3D=9(2x2x2+1),32(2x4x4),36(32+[1x2x2]).
So, presumably, if that rule applies, perhaps it works both forwards, in 4D=17C128cl136pl, and backwards, in 0D=2C0.5cl1pl?

My potentials table is shown at the bottum of this incredibly long post.

Now, for the ABCDecoding puzzle...
Jutomi wrote:Not all numbers are necessarily positive, whole numbers.
All so, feel free to point out any flaws I might have had in these puzzles. :mrgreen:
Good luck!
Attachments
9 of the third n 4 n 5.png
Here's an interesting cube.
9 of the third n 4 n 5.png (16.24 KiB) Viewed 4870 times
Your only little stinker that's absolutely NOT a z-bot by this name,
Jutomi~ :mrgreen:

Also, if you want to see my level list, here it is! :D
(Also: List of Hubs, WA Manual)
Oh, and my YT wonderland channel. Forgot about that.
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